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(2) Lower branch (return branch) running tension:
In the formula (upward), H takes a positive value, and vice versa.
C Tight edge tension and loose edge tension calculation
D The minimum allowable tension calculation according to the conveyor belt sag (1) The upper branch allows the minimum tension:
F sc =6.25ι c (W m +W 1 )g (24)
(2) The lower branch allows for minimum tension:
F=6.25ι r W 1 g (25)
E Four-point tension calculation of the conveyor belt When the side profile of the belt conveyor is relatively simple, the calculation of the belt conveyor head and the tail cylinder and the four-point tension T 1 to T 1 (Fig. 1) can be calculated. In order to obtain the maximum tension, minimum tension, tension, etc. of the conveyor belt; when the side profile of the belt conveyor is complicated, especially when the upper and lower undulations are up, it should be calculated point by point (consistent with the four-point tension calculation principle) The tension S 1 to S 2m (Fig. 1f) can obtain the maximum tension, the minimum tension, the tension and the like.
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a Calculation of tension when the effective tension F p ≥ 0 (1) When the head is driven (single roller or double roller):
The following formula applies to the calculation of the down-conveyor tension for parallel, up, and F p ≥ 0 (ω = 0.022):
T 1 =F 1 =F 2 +F p =T 2 +F p (26b)
T 3 =T 4 =T 2 +F r (26c)
When T 4 <F sc or F sr :
T 3 =T 4 =F sc or F sr (26d)
T 2 =T 3 -F r (26e)
T 1 =T 2 +F p (26f)
Tension distribution, as shown in Figure 1a.
(2) When the tail drive (single drum or double drum):
The following formula applies to the calculation of the down-conveyor tension for parallel, up, and F p ≥ 0 (ω = 0.022):
T 1 =F 1 =F 2 +F p =T 2 +F p (27b)
T 3 =T 4 =T 1 -F r (27c)
When T 2 <F sc or F sr :
T 2 =T sc or F sr (27d)
T 1 =T 2 +F p (27e)
T 3 =T 4 =T 1 -F r (27f)
Tension profile, as shown in Figure 1b.
(3) When the head and tail drive (2 sets of rollers, which can be composed of 2, 3 or 4 rollers):
The head roller has a total wrap angle of θ 1 , a friction coefficient of μ 1 , a drive motor power of M 1 , a tail drum total wrap angle of θ 2 , a friction coefficient of μ 2 , and a drive motor power of M 2 .
The following formula applies to the calculation of the tension of the downstream belt conveyor with dry parallel, up and F p ≥ 0 (ω = 0.022):
F 1 =F 21 +F p1 (28f)
F 12 =F 22 +F p2 (28g)
When F 21 <F 12 -F r :
T 4 =F 22 (28h)
T 3 =T 4 +F p2 (28i)
T 2 =T 3 -F r (28j)
T1=T2+F p1 (28k)
When F 21 >F 12 -F r :
T 2 =F 21 (28l)
T 1 =T 2 +F p1 (28m)
T 3 =T 2 +F r (28n)
T 4 =T 3 -F p2 (28o)
Tension distribution, as shown in Figure 1c.
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